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Claude Fable 5.1 Yana Bir Qadimiy Shifrni Yechdi

14-sentabr, 2026, 03:042 ko'rish5 daqiqa o'qish
Claude Fable 5.1 Yana Bir Qadimiy Shifrni Yechdi

Claude Fable 5.1 AI modeli 370 yillik Sir Thomas Urquhartning Cyphral Distich shifrini hal qildi. Bu shifr asrlar davomida hal qilinmagan edi.

Muammo

Claude Fable 5.1 AI modeliga ochiq vazifa berildi: Sir Thomas Urquhartning Cyphral Distich shifrini hal qilish. Bu shifr ikki qator 32 ta sonlardan iborat bo'lib, ularni yashirin matnga aylantirish kerak edi. Bu shifr 1899-yildan beri hal qilinmagan edi va bir necha marta qayta takrorlangan edi.

Ushbu shifrni hal qilish uchun turli usullar, jumladan chastotalik tahlil, almashtirish va homofonik almashtirish usullari sinab ko'rilgan, ammo hech biri samarali bo'lmagan.

Claude Fable 5.1 modeli 44 daqiqa ichida shifrni hal qildi. U ikkita asosiy tushuncha asosida ishlagan:

  • Shifr Urquhartning 32 Proquiritationsdan keyin joylashgan.
  • Shifrga qo'shimcha qilingan she'r shifrni hal qilish uchun kerakli izohlarni bergan.

Bu tushunchalar asosida, Claude Fable 5.1 modeli shifrni hal qildi va yashirin matnni topdi:

O GOD UPHOLD KING CHARLS THE SECOND AND MAKE HIM THE SUPREME RULER OF THIS LAND

5.3.27.38.32.14.21.8.66.8.70.39.5.9.12.18.2.3.56.5.1.7.3.2.13.19.3.25.9.3.16.6.
25.15.13.6.11.20.5.1.2.12.1.20.20.49.20.20.35.33.4.6.8.35.5.33.5.5.18.10.3.11.32.42.

Bu natija tarixiy jihatdan ham ma'nosi bor: Urquhart Charles II uchun duo yozgan edi.

Yana Bir Shifr

Urquhart The Jewel (1652) asarida yana bir, ancha katta shifrni qoldirgan edi — Cyphral Octastich. Bu shifr ham hal qilinmagan edi. Claude Fable 5.1 modeli ushbu shifrni ham hal qildi.

Natija:

GREAT LORD, MANTAINE THAT REGAL FAMILIE WHEREOF KING CHARLS THE SECOND IS THE HEAD, AND GRANT THAT HE MAY BEARE THE SUPREME SWEIGH WHERE ENGLISH, SCOTS AND IR[I]SH ARE BORNE AND BRED, AND [·········] THIS USURP'D AUTHORITIE REIGNE IN HIS ROYAL PREDECESSORS STEAD; LET HIM BE OUR SOLE CESAR, ARTUR, HECTOR, OUR EMPEROUR, KING, MONARCH AND PROTECTOR. AMEN, SO BE IT.

Result: the Cyfral Octastick is solved (all but nine letters)

Rule. The Jewel (1652) has exactly 284 numbered pages, and the octastick + decagram contain 285 numbers. The k-th number (counting straight through the eight lines and the Decagram) is a word index into page k of the book; take the word's first letter. Same idea as the Distich (number i → Proquiritation i), with pages instead of paragraphs — and, as in the Distich, Urquhart almost always picked the first word on the page starting with the letter he needed (231 of 275 readable positions are exact first-occurrence hits in the EEBO-TCP text; the other 44 are 1–3 words off for identifiable transcription reasons — hyphenated words at page tops, hyphenated compounds, "&", paragraph numbers, an untranscribed Greek phrase).

Plaintext (ottava rima, ABABABCC — a royalist prayer written in London, March 1652):

GREAT LORD, MANTAINE THAT REGAL FAMILIE
WHEREOF KING CHARLS THE SECOND IS THE HEAD,
AND GRANT THAT HE MAY BEARE THE SUPREME SWEIGH
WHERE ENGLISH, SCOTS AND IR[I]SH ARE BORNE AND BRED,
AND [·········] THIS USURP'D AUTHORITIE
REIGNE IN HIS ROYAL PREDECESSORS STEAD;
LET HIM BE OUR SOLE CESAR, ARTUR, HECTOR,
OUR EMPEROUR, KING, MONARCH AND PROTECTOR.
                        AMEN, SO BE IT.   (the Decagram)

Sweigh is Scots swey "sway, controlling power" — DOST records the exact idiom "to bear the swey" (c. 1600), and it rhymes with familie/authoritie.

Caveats, stated plainly:
- Line 4 is enciphered I‑R‑S‑H (pages 127–130): a slip for IRISH, or a deliberate contraction — "Irsh" gives the line exactly ten syllables.
- Line 5, letters 4–12 (pages 149–157) come out C‑O‑N‑E‑R‑T‑H‑T‑O — eight of the nine are exact first-occurrence hits, so this is genuinely what the TCP text yields, and it isn't readable. I tried page-shift, dropped-letter, misprinted-number and dictionary-lattice hypotheses; none gives English. Either Urquhart slipped here or numbers of this line were misprinted. The rest of the line (THIS USURP'D AUTHORITIE) is certain.
- From position 159 onward every number keys to page k−1: one page was used twice (or the printed "5.5" in line 5 is a dittography). Lines 6–8 and the decagram decode cleanly with that shift.
- No free page images of a 1652 Jewel exist (a subagent checked Google Books, HathiTrust, IA, NLS; the octastick sits on the final quire 3*² that the TCP copy lacks, but the main text and pagination are the same in all copies). Confirming the ±1 positions and the nine letters needs a physical copy or the 1983 Jack & Lyall edition.

Files: verify_octastick.py (prints all 285 positions with page/word/letter/offset; output in octastick_verification.txt), jewel_pages.py (page parser), firstocc.py/lattice.py (analysis tools), SOLUTION.md and FAMOUS-CIPHERS-STATUS.md updated, memory updated.

Sources: DOST swey(e n. (https://www.dsl.ac.uk/entry/dost/sweye_n), SND swey (https://dsl.ac.uk/entry/snd/swey), ESTC R203867 (via CERL) (https://datb.cerl.org/estc/R203867), Cipherbrain thread on the poems (https://scienceblogs.de/klausis-krypto-kolumne/2019/07/28/revisited-thomas-urquharts-encrypted-poems/), HCPortal record (https://www.cryptograms.hcportal.eu/web/#/ciphers/8).

Bu shifrni hal qilish uchun Claude Fable 5.1 modeli The Jewel kitobining har bir sahifasidagi so'zlarni ishlatgan.

Cheklovlar

Claude Fable 5.1 modeli shifrlarni hal qilishda bir nechta cheklovlarga duch keldi:

  • Bir nechta so'zlar noto'g'ri hal qilingan.
  • Bir nechta sahifalar takrorlangan.
  • Barcha sahifalarni tasdiqlash uchun fizik nusxalar kerak.

Claude Fable 5.1 modeli shifrlarni hal qilishda ko'rsatgan natijalari tarixiy jihatdan ham ma'nosi bor. Bu shifrlarni hal qilishda AI modellarining qobiliyatini ko'rsatdi.

Batafsil ma'lumot uchun: manba.

Asl manba: vals.ai

Manba: Hacker News
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